Super Caps 50F: Charge, Discharge & Heat Info

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The discussion focuses on the charge and discharge times and heat generation of Super Caps 50F. Key calculations for heat involve using the equivalent series resistance (ESR) and current draw, with power loss determined by the formula P=R*I^2. The charge and discharge times depend on load characteristics and can be found in the datasheet, which indicates a maximum discharge of 38A for one second. Concerns are raised about the lifespan of the capacitors under high current conditions, noting that they can last 500,000 cycles at 25°C, but temperature increases can significantly reduce their lifespan. The importance of consulting the spec sheet for ESR values is emphasized to ensure proper usage and longevity.
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I know they are low voltage that's fine. I want to find out charge and discharge time as well as heat from them.
 
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marmstrong941 said:
I know they are low voltage that's fine. I want to find out charge and discharge time as well as heat from them.
Have you looked at their datasheets?
 
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A good back of the envelope calculation for heat will be the ESR * your expected current draw squared

P=R*I^2

But that will only tell you power loss, not heat dissipation capabilities of the unit itself. If your power loss is greater than your heat dissipation limit, goodbye capacitor.

For charge and discharge time that will be dependent on your load and other properties (look up RC time constant), or are you talking about maximum. the mins and maxes can be found on the datasheet.
 
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Some...
http://cdn-reichelt.de/documents/datenblatt/B300/VEC3R0506QG.pdf
..say you can discharge at 38A for a second.

The internal resistance is around 10mOhm so there will be an IR voltage drop of perhaps 380mV at that current. The I2R power dissipation would be large 382* 0.01 = 14W.

I don't think they would last very long if abused like that. They give a life of 500,000 cycles (at 25C). If cycled every 2 seconds that would be about 12 days. Over the lifetime the ESR and hence power dissipation could also double. The general rule for some capacitors is that the lifetime halves for every 10C increase in temperature.
 
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I don't have r yet?
12 days would be great
 
marmstrong941 said:
I don't have r yet?
12 days would be great
Look on the spec sheet for the capacitors. you're looking for the ESR
 
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I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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