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esmeco
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In exercise i) I had to use the superposition to find the current through R2:removing the voltage source and sticking with the current source,this was my node equation:
Eq: v1/1000 + v1/1000 + 0.001=0
Solving for I2 the equation was:
V1-0/R2=I2 where I2=-5x10E-4
Removing the current source,the result for I2=2.5x10E-3
Adding those values in order to get the current passing through the original circuit I got:
I2=2x10E-3
The problem is,I'm not totally sure if this solution is right,because this's a practice exam whose solution isn't provided,so If someone could tell me if my equations are right I'd be glad!:)
http://i75.photobucket.com/albums/i281/esmeco/supeprositionethevenin.jpg
My other problem is in ii) where I need to find the Thevenin's voltage by opening the circuit on the load resistor (which is R2) and I'm not sure what is the voltage on the load resistor terminals(maybe 5 because it is connected to the voltage source?)...
The equation I got for the current on the short circuit was:
Eq: (Vo-5)/1000 + 0.001=0
Once again I'm not sure if this's right...Just one more question:DO we have to add the resistors on the short circuited circuit in order to calculate Isc?
Thanks for your time and for all the replies!
Eq: v1/1000 + v1/1000 + 0.001=0
Solving for I2 the equation was:
V1-0/R2=I2 where I2=-5x10E-4
Removing the current source,the result for I2=2.5x10E-3
Adding those values in order to get the current passing through the original circuit I got:
I2=2x10E-3
The problem is,I'm not totally sure if this solution is right,because this's a practice exam whose solution isn't provided,so If someone could tell me if my equations are right I'd be glad!:)
http://i75.photobucket.com/albums/i281/esmeco/supeprositionethevenin.jpg
My other problem is in ii) where I need to find the Thevenin's voltage by opening the circuit on the load resistor (which is R2) and I'm not sure what is the voltage on the load resistor terminals(maybe 5 because it is connected to the voltage source?)...
The equation I got for the current on the short circuit was:
Eq: (Vo-5)/1000 + 0.001=0
Once again I'm not sure if this's right...Just one more question:DO we have to add the resistors on the short circuited circuit in order to calculate Isc?
Thanks for your time and for all the replies!
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