Superposition net gravitational force

In summary, the conversation discusses finding the net gravitational force on a central sphere with mass .00424 kg, which is surrounded by four spheres with masses .00372 kg, .00958 kg, .00408 kg, and .00835 kg. The conversation mentions using the equation F = G*Ma*Mb/r^2 in unit-vector notation to find the force in the x-direction and y-direction. It is suggested to use trigonometry and to consider the distance between particles when calculating the net force. The conversation also reminds to be careful with the components in vector notation, as vertical and horizontal components are not related in the equation.
  • #1
sophzilla
20
0
I would appreciate any help on this problem:

In Fig. 14-18a, a square of edge length .232m is formed by four spheres of masses m1 = .00372 kg, m2 = .00958 kg, m3 = .00408 kg, and m4 = .00835 kg. In unit-vector notation, what is the net gravitational force from them on a central sphere with mass m5 = .00424 kg?

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I started out by using F = G*Ma*Mb/r^2. So for the x-direction, it would be something like:

Fi = G*M3*M4/r^2 + G*M1*M2/r^2, and similar things for the y-direction.

But I don't know how to include the m5 into my equations. Do I have to involve angles and trig functions?
 
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  • #2
Okay, here's the first thing that needs to happen. Just as a forwarning, trig will be used to the fullest extent. Remeber that when you want to find the net gravitational force, you don't include the particle that you are ovbserving. The only part that it plays is the distance from the other particles. Also, remeber that particles on either side of a central particle have cancelling effects, depending on the masses and the radial distances.
 
  • #3
Be careful with your components in the vector notaion. Remeber that vertical components of force vectors have nothing to do with the horizontal with tregards to the algebraic setup.
 

FAQ: Superposition net gravitational force

What is superposition net gravitational force?

Superposition net gravitational force is the combined gravitational force exerted by multiple objects on a single object. It takes into account the mass and distance of each object to calculate the overall gravitational force.

How does superposition net gravitational force differ from normal gravitational force?

Normal gravitational force refers to the force between two objects, while superposition net gravitational force takes into account the gravitational forces of multiple objects on a single object. It is a more complex calculation that considers the combined effects of all objects.

How is superposition net gravitational force calculated?

To calculate superposition net gravitational force, you must first determine the mass and distance of each object from the single object. Then, use the formula F = G * (m1 * m2) / d^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between them. Repeat this calculation for each object and then add the individual gravitational forces together to get the net force.

Can superposition net gravitational force be negative?

No, superposition net gravitational force cannot be negative. Gravitational force is always attractive, so the net force will always be positive or zero. A negative value would indicate a repulsive force, which is not possible with gravity.

How does superposition net gravitational force relate to Newton's Law of Universal Gravitation?

Superposition net gravitational force is a more complex application of Newton's Law of Universal Gravitation. It takes into account the gravitational forces of multiple objects rather than just two. Newton's law states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. Superposition net gravitational force extends this concept to include multiple objects.

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