Superposition Question, electric circuits

In summary, the problem involves a circuit with a 10 ohm resistor, a dependent voltage source that equals 3 times Vab, a 4V independent voltage source, and a 2A independent current source. The question is asking to find Vab using superposition. The given information also includes the use of Ohm's Law, KCL, and KVL. The attempt at a solution involves breaking down the circuit, but the presence of the dependent voltage source makes it different from the examples in the textbook. The final question is what is the current through the 10 ohm resistor and what are the voltages at the two ends of this resistor.
  • #1
string_656
21
0

Homework Statement



^^^^ = resistor = 10 ohm
<> = 3*Vab Dependent voltage. (the voltage equals 3 times Vab)
0 = voltage source 4 v (inderpendant)
o = Inderpendant Current source 2 A



|--^^^^---<>---------a +
| + + - |
0 o Vab
| - |
|-----------------------b -

Question asks, Find Vab (the voltage across a and b) using superposition



Homework Equations


Well there's lots, ohms, KCL, KVL etc,


The Attempt at a Solution


I want to attempt it, but i don't no how to break this down, as all the examples in the txt book don't have the dependant votlage source, and in the examples they are solving for a voltage across a resistor.

Any ideas? thanks
ps i also uploaded the image just incase the one above didnt work once posted
 

Attachments

  • untitled.bmp
    142.4 KB · Views: 603
Physics news on Phys.org
  • #2
What is the current through the 10 ohm resistor?
What are the voltages at the two ends of this resistor?
 
  • #3



my response would be as follows:

Superposition is a powerful tool that allows us to analyze complex systems by breaking them down into simpler parts. In this case, we can use superposition to solve for Vab by considering the effects of each source individually.

First, we can consider the effect of the voltage source alone by setting the current source to 0 A. This results in a simple circuit with a series connection of a 4 V voltage source and a 10 ohm resistor. Using Ohm's law, we can calculate the voltage across the resistor as 4 V. This voltage is equal to Vab since there are no other elements in the circuit.

Next, we can consider the effect of the current source alone by setting the voltage source to 0 V. This results in a circuit with a parallel connection of the 10 ohm resistor and the dependent voltage source. Using Kirchhoff's Current Law, we can calculate the current through the dependent voltage source as 2 A. This current is equal to 3 times Vab, so Vab must be equal to 2/3 V.

Finally, we can combine these two results using the principle of superposition. This states that the total voltage across Vab is equal to the sum of the voltages calculated in each individual case. Therefore, Vab = 4 V + 2/3 V = 14/3 V.

In summary, by using superposition, we were able to solve for Vab by considering the effect of each source individually and then combining the results. This method can be applied to more complex circuits as well, making it a valuable tool for circuit analysis.
 

FAQ: Superposition Question, electric circuits

What is the concept of superposition in electric circuits?

The concept of superposition in electric circuits is based on the principle that the total response of a circuit is equal to the sum of individual responses of each component. This means that when multiple sources are present in a circuit, the resulting current or voltage at any point in the circuit can be determined by considering each source separately while keeping the other sources turned off.

How does superposition help in analyzing complex electric circuits?

Superposition helps in analyzing complex electric circuits by breaking down the circuit into smaller, simpler circuits that are easier to analyze. By considering each source separately, the overall response of the circuit can be determined without having to solve a complex set of simultaneous equations.

What are the limitations of using superposition in electric circuits?

The main limitation of using superposition in electric circuits is that it only applies to linear circuits, where the relationship between the voltage and current is linear. It also assumes that the circuit components are independent of each other, which may not always be the case in practical circuits.

Can superposition be applied to AC circuits?

Yes, superposition can be applied to AC circuits as long as the circuit is linear and the sources are sinusoidal. In AC circuits, the different sources are considered separately at the same frequency and the total response is obtained by adding the individual responses using complex numbers.

How is superposition different from the principle of superposition in other fields?

The principle of superposition in electric circuits is similar to the principle of superposition in other fields, such as mechanics or optics. However, in electric circuits, the principle of superposition applies to both steady-state and transient conditions, whereas in other fields it may only apply to steady-state conditions.

Similar threads

Replies
2
Views
2K
Replies
7
Views
2K
Replies
4
Views
1K
Replies
3
Views
2K
Replies
7
Views
2K
Replies
7
Views
2K
Replies
5
Views
2K
Back
Top