Suppose there are 2 defective among five items

  • Thread starter shinkansenfan
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In summary, if you have two items that are both defective, the probability you found the first defective item is 1 out of 10.
  • #1
shinkansenfan
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Homework help:

suppose there are 2 defective among five items, you test one item at a time until you identify the second defective. find:

1. you need at most 3 tests.
2.given the second defective item found at the 3rd test, find the Probability that you found the first defective at the 1st test.
 
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  • #2
One, I don't think this is the right section for your question.

Unless you mean you expect to only check 3 times I don't think that is right.
Let's say I check one and it's fine, the second one I check is defective and the third one I check is defective. I would need one more test to see which one out of the two left is defective. And that still leaves the question of do I have to check the last one to ensure it's defective for this problem or can we assume that we can use elimination and not have to check the one we know to be defective?
The last part is just a conditional probability, try Bayes Theorem.
 
  • #3
Hi shinkansenfan. jwatts is right that you should be using the separate forums for homework questions.

But since you're here: If you are asking for the probabilities of the events in your questions, think about all the possible ways that two of five ordered items can be defective.

Consider a simpler example: one of two items is defective. There are two possibilities in this simple case:
A. Item 1 is defective, Item 2 is not.
B. Item 1 is not, Item 2 is defective.

What is the probability Item 1 is defective? Just count! In one of the two cases, Item 1 is defective, so the probability is 0.5.

If two of three items are defective,
A. I1 defective, I2 defective, I3 not.
B. I1 defective, I2 not, I3 defective.
C. I1 not, I2 defective, I3 defective.

What is the probability that Item 1 is defective? 2/3. Can you answer versions of your two questions in this simpler case?
What is the probability you need at most two tests to find the second defective item?
Given that you find the second defective item is Item 3, what is the probability you found Item 1 to be the first defective item?

Use the same logic to solve the full question that you asked, writing out all 10 possibilities if you really have to. (Hint: write 11000 for Items 1 and 2 defective, Items 3-5 not).
 
Last edited:

FAQ: Suppose there are 2 defective among five items

How would you determine the probability of randomly selecting a defective item from a batch of five?

The probability of randomly selecting a defective item from a batch of five would depend on the total number of defective items in the batch. If there are two defects among five items, the probability would be 2/5 or 40%.

Is it possible to have more than two defective items in a batch of five?

Yes, it is possible to have more than two defective items in a batch of five. The number of defects would depend on the quality control measures during production and the nature of the items being produced.

How would you identify the two defective items among the five?

The identification of the two defective items would require a thorough inspection or testing of each item in the batch. This could involve visual inspection, functional testing, or other methods depending on the nature of the items.

What is the likelihood of getting a non-defective item from this batch?

The likelihood of getting a non-defective item from this batch would be 3/5 or 60%. This is because out of the five items, three are non-defective and two are defective.

Can the probability of having two defective items out of five change over time?

Yes, the probability of having two defective items out of five can change over time. This could be due to changes in the production process, improvements in quality control measures, or other factors that may affect the likelihood of defects in the items.

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