- #1
daudaudaudau
- 302
- 0
Hi. Does anyone know how to prove that
[tex]
\int \int dS \hat \mathbf n = \int \mathbf r \times d\mathbf r
[/tex]
i.e., the surface integral of the unit normal vector equals the line integral on the r.h.s. ?
[tex]
\int \int dS \hat \mathbf n = \int \mathbf r \times d\mathbf r
[/tex]
i.e., the surface integral of the unit normal vector equals the line integral on the r.h.s. ?