Surface tension, capillary action, viscous fluid

[amjber2]

I was having trouble with this problem. please let me know how to approach this. thanks.

The density of ice is 920 kg/m3, and that of seawater is 1030 kg/m3. What fraction of the total volume of an iceberg is exposed?

 

[andrevdh]

Use Archimede's principle. The amount of seawater displaced by the iceberg - the weight of the seawater displaced by the volume of the iceberg below the surface $V_{below}$ - needs to be equal to the weight of all of the iceberg.

 

[kyle8921]

Hello,

It seems like you have a good understanding of the concepts of surface tension, capillary action, and viscous fluid. To approach this problem, we can use the concept of buoyancy and the relationship between density and volume.

First, we can calculate the density of the iceberg using the given information. Since ice is less dense than water, the density of the iceberg will be less than 1030 kg/m3. Let's assume it is 930 kg/m3.

Next, we can use the formula for buoyancy (Fb=ρVg) to calculate the volume of the iceberg that is submerged in water. We know the density of water (1030 kg/m3) and the density of the iceberg (930 kg/m3), so we can rearrange the formula to solve for the volume (V).

V = Fb/ρg

Since the iceberg is floating, the buoyant force (Fb) is equal to the weight of the displaced water. We can calculate this using the density of water and the volume of the submerged portion of the iceberg (V).

Fb = ρwV

Now we can plug this into the formula for volume.

V = ρwV/ρg

Simplifying, we get V = ρw/ρg.

Plugging in the values, we get V = (1030 kg/m3)/(930 kg/m3) = 1.11.

This means that the volume of the submerged portion of the iceberg is 1.11 times the total volume of the iceberg. Therefore, the fraction of the total volume of the iceberg that is exposed is 1 - 1/1.11 = 0.1 or 10%.

I hope this helps you approach similar problems in the future. Keep up the good work in your studies of science!

Best,