Solve the first two equations for $a$ and $b$. You should get $a = \dfrac{4y+3}{x(y-x)}$, $b = \dfrac{-4x-3}{y(y-x)}.$ Now substitute those values of $a$ and $b$ into the third equation. That should lead to $4xy+3x+3y-3=0.$jacks said:If [tex]a\;,b\;,x\;,y[/tex] satisfy [tex]\begin{Bmatrix} ax+by=4\\\\
ax^2+by^2=-3 \\\\
ax^3+by^3=-3 \\\\
\end{Bmatrix}[/tex]. Then [tex](2x-1)(2y-1)=[/tex]
A system of equations is a set of two or more equations that contain the same variables. The solution to a system of equations is the values of the variables that make all of the equations true.
There are several methods for solving a system of equations, including substitution, elimination, and graphing. The method used depends on the type of equations and the number of variables in the system.
Solving a system of equations allows us to find the values of the variables that satisfy all of the equations. This is useful in real-world applications such as finding the intersection point of two lines or determining the optimal solution to a problem.
To graph a system of equations, first rearrange each equation in slope-intercept form (y = mx + b). Then, plot the y-intercept (b) and use the slope (m) to find additional points on the line. Repeat this process for each equation and plot all points on the same coordinate plane to see where the lines intersect.
The solution to this system of equations is not a single point, but rather an infinite number of points that satisfy the equation. This is because the equation is in factored form and can be expanded into multiple equations. To find the solution, you would need additional information or constraints.