Take the anti derivative of (X^2)/sqrt(1-x)soln'let u=1-x

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The discussion focuses on finding the antiderivative of (X^2)/sqrt(1-x) using substitution. The user initially substitutes u=1-x, leading to an incorrect expression. They later clarify the correct approach by rewriting the integral as -∫(1-u)^2/sqrt(u) du. The integration involves distributing the u^(-1/2) term over the quadratic before integrating. The conversation emphasizes the importance of careful substitution and distribution in solving integrals.
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take the anti derivative of (X^2)/sqrt(1-x)

soln'... let u=1-x... then -du=dx and x^2 = (1-u)^2 (sub back in)...

this gives me -2*u^(1/2)*(15-10*u+3*u^2) /15... (sorry for lack of proper terms)


anyway, this turns out to be wrong...where did i go wrong here?
 
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Try this:

\int \frac{x^2}{\sqrt{1-x}}dx = -\int \frac{(1-u)^2}{\sqrt{u}}du = -\int u^{-\frac{1}{2}}(1-2u+u^2) du

then distribute the u^{-\frac{1}{2}} term over the quadratic and integrate
 
yeah...that's what i was getting but it was in a different form. Thanks a lot !1
 
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