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RTW69
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Homework Statement
Determine the speed with which the Earth would have to turn to rotate on its axis so that a person on the equator would weigh 3/4 as much
Homework Equations
VT=r*ω ; Vi=469 m/s is tangential velocity of earth
ƩF=M*ac=m*Vt^2/r
The Attempt at a Solution
The positive direction is toward the center of the earth.
From ƩF=m*ac
Initial: m*g-Ni=m*Vi^2/r
Final: 3/4m*g-Nf=m*Vf^2/r
Since m*g is the same for initial and final state I assume that Ni=Nf
Therefore:3/4m*g-[mg-m*Vi^2/r]=m*Vf^2/r or
Vf=Sqrt(Vi^2-r*g/4)
I have a sign error. I end up taking the square root of a negative number but the physics looks OK. Suggestions?