- #1
frasifrasi
- 276
- 0
Ok, we are asked to determined the degree of the the taylor polynomial about c =1 that should be used to approximate ln (1.2) so the error is less than .001
the book goes throught the steps and arrives at:
|Rn(1.2)| = (.02)^(n+1)/(z^(n+1)*(n+1)
but then, it states that
(.02)^(n+1)/(n+1) < .001
and there is an error pointing this expression to
1000 < (n+1)(5^(n+1))
--> I have no idea how the book arrived at this second expression, could anyone please explain?
- Also, if anyone knows, why was the z term left out in the second step?
Thank you.
the book goes throught the steps and arrives at:
|Rn(1.2)| = (.02)^(n+1)/(z^(n+1)*(n+1)
but then, it states that
(.02)^(n+1)/(n+1) < .001
and there is an error pointing this expression to
1000 < (n+1)(5^(n+1))
--> I have no idea how the book arrived at this second expression, could anyone please explain?
- Also, if anyone knows, why was the z term left out in the second step?
Thank you.