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TheFerruccio
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I have a couple of general questions, combined with this one specific question
Find the Taylor or MacLauren series centered about the given value for the following function, determine the radius of convergence
[tex]\mathrm{Ln}\ z[/tex], 2
I know that
[tex]\mathrm{Log}\ z = \ln{|z|} + i\left(\mathrm{Arg}\ z\right)[/tex]
But, I don't know where to go from here, nor do I know how to find a relevant pattern for find the radius of convergence. It might just be an issue of not remembering this from Calc 2.
Also, from earlier questions, if have some series that's in terms of something like [tex]\left(2z+i\right)^{2n}[/tex] Can I just simplify it to be in terms of [tex]2^{2n} \left(z+\frac{i}{2}\right)^{2n}[/tex], then have the radius be the square root of whatever the radius would be if it was in terms of [tex]\left(z+\frac{i}{2}\right)^{n}[/tex]? Then, if the radius is less than 1/2, then it can be determined that the series about the point [tex]z+\frac{i}{2}[/tex] does not converge?
Homework Statement
Find the Taylor or MacLauren series centered about the given value for the following function, determine the radius of convergence
Homework Equations
[tex]\mathrm{Ln}\ z[/tex], 2
The Attempt at a Solution
I know that
[tex]\mathrm{Log}\ z = \ln{|z|} + i\left(\mathrm{Arg}\ z\right)[/tex]
But, I don't know where to go from here, nor do I know how to find a relevant pattern for find the radius of convergence. It might just be an issue of not remembering this from Calc 2.
Also, from earlier questions, if have some series that's in terms of something like [tex]\left(2z+i\right)^{2n}[/tex] Can I just simplify it to be in terms of [tex]2^{2n} \left(z+\frac{i}{2}\right)^{2n}[/tex], then have the radius be the square root of whatever the radius would be if it was in terms of [tex]\left(z+\frac{i}{2}\right)^{n}[/tex]? Then, if the radius is less than 1/2, then it can be determined that the series about the point [tex]z+\frac{i}{2}[/tex] does not converge?
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