- #36
Brian T
- 130
- 31
Good. Now, what force(s) is/are acting on that block?
Tension is acting on that block.Brian T said:Good. Now, what force(s) is/are acting on that block?
Is that the acceleration for the system then?Brian T said:So, you know the force necessary to accelerate the block (~28) and you know there is only one force acting on the block, so...
So I have my answer?Brian T said:You know the force needed to accelerate the block, and tension is the only force pulling it, therefore, the tension is equal to the force needed to accelerate it (~28 N)
Okay. Thank you so much for your help! I really appreciate you taking the time to help me!Brian T said:Yes. Another way to reach the answer is by looking at M2:
We know that, since M2 is 3.9 kg, it should have a net force acting on it of:
F2net = ma
F2net = (3.9 kg)(4.10995 m/s^2)
F2net = 16.029 N.
Now the net force on block 2 should equal to the sum of the forces. The two forces are tension (left) and the pull (right). We have:
F2net = Fpull + T
F2net we just calculated is 16.029 N.
Fpull you previously calculated was 41.0995 N. Plugging it in:
16.029 N = 41.0995 N + T
Solve and get T ~ -28 (negative indicating left directed force. There is also an equal tension pulling to the right on block 1, which is the force you calculated).
No problem, glad I could help. Let me know if you have any more questions about that. :Dlitz057 said:Okay. Thank you so much for your help! I really appreciate you taking the time to help me!
I will! Thanks again!Brian T said:No problem, glad I could help. Let me know if you have any more questions about that. :D