Tension in the cable of the lift

In summary: When lift is moving upward, the tension is twice the tension when the lift moves downward. This is due to the mass of the lift being twice the mass of the object being lifted, and the net acceleration being twice as much.
  • #1
jatin1990
21
0

Homework Statement



The tension in the cable supporting a lift moving upward is twice the tension when the lift moves downward. What is the acceleration of the lift?

Homework Equations





The Attempt at a Solution


i think its only conceptual but still please show me the way how to think about it.
Thank you.
 
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  • #2
welcome to pf!

hi jatin19901! welcome to pf! :wink:

apply good ol' Newton's second law to find the relationship between a g and T for the two cases …

what do you get? :smile:
 
  • #3


tiny-tim said:
hi jatin19901! welcome to pf! :wink:

apply good ol' Newton's second law to find the relationship between a g and T for the two cases …

what do you get? :smile:
i am doing it like this , when lift is moving downward then , Tension(T) = Mass(m) * Net Acceleration ( Acc. due to gravity(g)+ Lift acceleration(a))
And when lift is moving upward then : 2T = M * (g-a) , and finding out the relation between a and g , i am getting , a=-g/3 , i have a option of g/3 , and i am getting -g/3 .
please correct me where i am wrong.
 
Last edited:
  • #4
jatin1990 said:
Tension(T) = Mass(m) * Net Acceleration ( Acc. due to gravity(g)+ Lift acceleration(a))

no no no no noooo :redface:

never do that, there is only one acceleration for one body

in other words: you can put as many forces as you like on the LHS of F = ma, but you can only put one acceleration on the RHS​

(of course, you can subtract accelerations of different bodies, to get the relative acceleration of the two bodies, but that's not this case)

g is not an acceleration (on the RHS), mg is a force (on the LHS)

try again! :smile:
 
  • #5
tiny-tim said:
no no no no noooo :redface:

never do that, there is only one acceleration for one body

in other words: you can put as many forces as you like on the LHS of F = ma, but you can only put one acceleration on the RHS​

(of course, you can subtract accelerations of different bodies, to get the relative acceleration of the two bodies, but that's not this case)

g is not an acceleration (on the RHS), mg is a force (on the LHS)

try again! :smile:

I do not got your last line.
 
  • #6
you mean? …
g is not an acceleration (on the RHS), mg is a force (on the LHS)

in F = ma, the only a on the RHS is the actual acceleration (what you, for some reason, are calling the "net acceleration" :frown:)

on the LHS, you put all the forces, and that includes the weight, mg :smile:
 
  • #7
tiny-tim said:
you mean? …


in F = ma, the only a on the RHS is the actual acceleration (what you, for some reason, are calling the "net acceleration" :frown:)

on the LHS, you put all the forces, and that includes the weight, mg :smile:
oh ok , yes got the answer as A = g/3 , but i don't know whether it is correct or not , can u please check it. One more thing i have some questions to ask , can you please answer them here or do i need to start a another thread?
Thank you.
 
  • #8
jatin1990 said:
oh ok , yes got the answer as A = g/3 , but i don't know whether it is correct or not , can u please check it.

if you want us to check your calculations, you need to show them :wink:
One more thing i have some questions to ask , can you please answer them here or do i need to start a another thread?

always start another thread :smile:
 
  • #9
when lift is moving upward i got , 2T+mg=-ma and when lift is moving downward , T+mg=ma , and then equate the T from both equations , is it right?
 
  • #10
jatin1990 said:
when lift is moving upward i got , 2T+mg=-ma and when lift is moving downward , T+mg=ma

uhhh? :confused:

how can the tension be in the same direction as the weight??​
 
  • #11
tiny-tim said:
uhhh? :confused:

how can the tension be in the same direction as the weight??​

Sorry for my stupidity , now i got it. As i am touching physics after two years , so this is the result. I hope i will get my command back upon physics with the help of this forum.
Thank you Tiny Tim for answering my questions very quickly every time.
 

FAQ: Tension in the cable of the lift

What causes tension in the cable of a lift?

The tension in the cable of a lift is caused by the weight of the lift and its occupants. As the lift moves up and down, the cable experiences forces that create tension, which helps to support the weight of the lift.

How is tension in the cable of a lift calculated?

The tension in the cable of a lift is calculated using the equation T = mg + ma, where T is the tension, m is the mass of the lift and its occupants, g is the acceleration due to gravity, and a is the acceleration of the lift. This equation takes into account the weight of the lift and the additional forces that act on it.

Is there a maximum tension that the cable of a lift can handle?

Yes, there is a maximum tension that the cable of a lift can handle. The maximum tension is determined by the strength and weight capacity of the cable itself. It is important to ensure that the tension in the cable does not exceed this maximum limit to prevent potential accidents.

How does tension in the cable affect the movement of a lift?

The tension in the cable affects the movement of a lift by providing the necessary force to support the weight of the lift and its occupants. As the lift moves up and down, the tension in the cable changes, causing the lift to accelerate or decelerate accordingly.

Can changes in temperature affect the tension in the cable of a lift?

Yes, changes in temperature can affect the tension in the cable of a lift. As the temperature changes, the cable may expand or contract, which can alter its length and affect the tension. It is important to account for these temperature changes when calculating the tension in the cable to ensure the safety and stability of the lift.

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