Tension with circular motion on incline

In summary, an energetic father is standing at the top of a conical hill, spinning his child around on a cart with a rope that is 2.3 meters long. The hill has sides inclined at 23 degrees and the father keeps the rope parallel to the ground with negligible friction. The question asks for the tension in the rope, with proper units. The forces acting on the cart and child include a normal force perpendicular to the hill, the force of their weight, and a tension force. The tension force can be resolved into two components, with Ty balancing the weight and Tx providing the centripetal force for circular motion.
  • #1
racer98jc
6
0

Homework Statement



An energetic father stands at the summit of a conical hill as he spins his 23 child around on a 5.6 cart with a 2.3--long rope. The sides of the hill are inclined at 23 . He keeps the rope parallel to the ground, and friction is negligible.

What is the tension in the rope?

Homework Equations


The Attempt at a Solution

 
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  • #2
Use proper units for the quantities.

Now indentify the forces acting on the child and the cart.
 
  • #3
the child and the cart act as one.
there is a normal force perpendicular with the hill. there is also the force of its own weight. and a tension force.

right?
 
  • #4
is that right?
 
  • #5
Resolve the tension into two components.

Ty balances the weight of the cart and child.

Tx provides the centripetal force which keeps the cart and the child in the circular motion.

Now proceed.
 

FAQ: Tension with circular motion on incline

What is tension with circular motion on incline?

Tension with circular motion on incline refers to the force that is experienced by an object as it travels in a circular path along an inclined surface. This force is exerted by the string or rope that is attached to the object and is constantly changing in direction and magnitude as the object moves.

What factors affect the tension in circular motion on incline?

The tension in circular motion on incline is affected by several factors including the mass of the object, the speed at which it is moving, the angle of the incline, and the radius of the circular path. These factors determine the centripetal force required to keep the object moving in a circular path and therefore, affect the tension.

How is tension calculated in circular motion on incline?

The tension in circular motion on incline can be calculated using the formula T = mv²/r + mg sinθ, where T is the tension, m is the mass of the object, v is the speed, r is the radius of the circular path, g is the acceleration due to gravity, and θ is the angle of the incline.

Is tension always present in circular motion on incline?

Yes, tension is always present in circular motion on incline as it is required to provide the necessary centripetal force to keep the object moving in a circular path. Without tension, the object would move in a straight line and not along the incline.

How does the angle of the incline affect the tension in circular motion?

The angle of the incline has a significant effect on the tension in circular motion. As the angle increases, the tension also increases because the centripetal force required to keep the object moving in a circular path also increases. This is because the component of the object's weight along the incline also increases with the angle, requiring a higher tension to balance it out.

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