Terminal Voltage: Solving for 12V Motorcycle Battery Charger

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To find the terminal voltage of a 12V motorcycle battery with a 0.520 Ω internal resistance while charging at 11.7 A, the equation ΔV = ε - IR is used. The initial calculation resulted in a terminal voltage of 5.916 V, which was incorrect. The misunderstanding arose from not accounting for the direction of the charging current, which should be treated as negative. After clarification, it was noted that the charger’s current input affects the terminal voltage calculation, leading to the correct interpretation of the problem. Understanding the relationship between terminal voltage, internal resistance, and battery emf is crucial for accurate calculations.
burnst14
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Homework Statement



(a) Find the terminal voltage of a 12.0-V motorcycle battery having a 0.520 Ω internal resistance, if it is being charged by a current of 11.7 A.

(b) What is the output voltage of the battery charger?


Homework Equations



ΔV = ε - IR
or
Vterminal = ε - IR

The Attempt at a Solution



ΔV = 12 - (11.7*0.52) = 5.916 = Vterminal

This is incorrect. WebAssign also returned this information:

"What is the sign of the current if it is flowing into the positive terminal of the battery? How is terminal voltage related to the internal resistance and battery emf?"

So I made it negative and submitted the response: -5.916

Still wrong. What am I missing?
 
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You have an external voltage (the "charger") supplying a given current into the battery (which includes an internal resistance). Draw the circuit and pencil in the current and potential drops for the given current.
 
My physics teacher was able to help me. I was missing the fact that the current would have to be made negative since the charger was inputting a current. Thanks though!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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