- #1
chwala
Gold Member
- 2,746
- 387
- Homework Statement
- See attached
- Relevant Equations
- stats
Looking at stats today,
In my working i have;
Let
##H_0 = μ_1=μ_2##
v/s
##H_1 = μ_1-μ_2≠ 0##
then,
##\bar x = \dfrac{134+83+...+123}{12}=120##
##\bar y = \dfrac{70+118...+94}{7}=101##
##t=\dfrac{\bar x- \bar y}{S_p ⋅\sqrt {\dfrac{1}{n_1}+\dfrac{1}{n_2}}}##
##t=\dfrac{120-101}{21.21 \sqrt {\dfrac{1}{12}+\dfrac{1}{7}}}##
##t=1.89##
and,
##t_{[17, 0.05]} =2.11##
since ##t_{calculated} < t_{[17, 0.05]}## that is ##1.89 < 2.11## we accept the null hypothesis that the ration are not different from one another and reject the alternative hypothesis that the ration are different from one another.
your insight is welcome...cheers.
In my working i have;
Let
##H_0 = μ_1=μ_2##
v/s
##H_1 = μ_1-μ_2≠ 0##
then,
##\bar x = \dfrac{134+83+...+123}{12}=120##
##\bar y = \dfrac{70+118...+94}{7}=101##
##t=\dfrac{\bar x- \bar y}{S_p ⋅\sqrt {\dfrac{1}{n_1}+\dfrac{1}{n_2}}}##
##t=\dfrac{120-101}{21.21 \sqrt {\dfrac{1}{12}+\dfrac{1}{7}}}##
##t=1.89##
and,
##t_{[17, 0.05]} =2.11##
since ##t_{calculated} < t_{[17, 0.05]}## that is ##1.89 < 2.11## we accept the null hypothesis that the ration are not different from one another and reject the alternative hypothesis that the ration are different from one another.
your insight is welcome...cheers.
Last edited: