- #1
Chris L T521
Gold Member
MHB
- 915
- 0
\[\int_0^{\infty}e^{-x^2}\,dx=\frac{\sqrt{\pi}}{2}\]
This is inline: \(\frac{\sqrt{b^2-4ac}}{2a}\)
Other centered equation
$$\Gamma(x)=\int_0^{\infty}e^{-t}t^{x-1}\,dt $$
This is inline: \(\frac{\sqrt{b^2-4ac}}{2a}\)
Other centered equation
$$\Gamma(x)=\int_0^{\infty}e^{-t}t^{x-1}\,dt $$
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