- #1
peripatein
- 880
- 0
Homework Statement
How does the RC-link help with adding ripple to the signal? What would happen if the capacitor was removed (short-circuited)?
Homework Equations
The Attempt at a Solution
I believe that the role of the capacitor is to pass on the AC voltage. Initially the capacitor is charged to a voltage of 10V, the DC voltage in the circuit, and hence the passing on of the ripple is made possible from the AC source. The voltage potential on the resistor connecting the DC source and the capacitor enables oscillations without opposing the DC voltage. I also think that using a greater capacitor would entail a greater time constant but the passing on of the ripple would also be better. Other than that I am truly not sure; moreover, I am not certain it actually answers the question, as required. I'd be thankful for some guidance here.