The Chain Rule - Simple but Complicated Problem

In summary, the conversation is about finding the value of (f o g)' at the given value of x using the chain rule in calculus. The person is struggling with their attempt and the answer in the book, and is asking for clarification and explanation. The correct application of the chain rule is (f \circ g)'(x) = f'(g(x))g'(x), where f(x) = x^5 + 1 and g(x) = \sqrt{x}.
  • #1
zaboda42
32
0
Find the value of (f o g)' at the given value of x.

f(u) = u5 + 1
u = g(x) = sqrt(x)
x = 1

Ok so the section is based on the chain rule and came right out of my calculus book. I seem to be doing the problem right, i check my attempt over a few times and cannot seem to find the problem (the answer in the book is different from my answer).

Here's my attempt:

f(g(x)) = (sqrt(x))5 + 1
d/dx ((sqrt(x))5) + 1 = (5(sqrt(x)))4

Ok the problem is with the derivative of the function. When my book does the problem they get 5/2 but don't explain the procedure. Anyone care to explain, please?
 
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  • #2
Well, it would probably help us if you showed all of your steps but looking at your answer, it looks like you're confused about the application of the chain rule. Try again, showing all of your steps and remember:

[tex](f \circ g)'(x) = f'(g(x))g'(x)[/tex]

Edit: It might also help to note that [itex]f(x) = x^5 + 1[/itex] and [itex]g(x) = \sqrt{x}[/itex]
 

FAQ: The Chain Rule - Simple but Complicated Problem

What is the chain rule in calculus?

The chain rule is a rule in calculus that is used to find the derivative of composite functions. It states that the derivative of a composite function is equal to the derivative of the outer function multiplied by the derivative of the inner function.

Why is the chain rule important?

The chain rule is important because it allows us to find the derivative of complex functions by breaking them down into simpler functions. It is also used in many real-world applications, such as in physics, engineering, and economics.

How do you apply the chain rule?

To apply the chain rule, you first identify the inner and outer functions in the composite function. Then, you take the derivative of the outer function and multiply it by the derivative of the inner function. Finally, you substitute the inner function back into the derivative of the outer function.

Can the chain rule be used for higher order derivatives?

Yes, the chain rule can be applied to find higher order derivatives of composite functions. To find the second derivative, you apply the chain rule twice, and so on for higher order derivatives.

How can I practice and improve my understanding of the chain rule?

You can practice and improve your understanding of the chain rule by solving various problems and exercises that involve composite functions. You can also watch online tutorials or attend workshops on the topic, and seek help from a teacher or tutor if needed.

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