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The combustion of petrol can be approximately represented by the equation
2C8H18(g) + 25O2 -----> 16CO2 + 18H2O
The density of Ocatane is 0.7 gcm(cubed)
What mass of oxygen is used up when 1L of petrol is burnt in a car engine?
ATTEMPT
0.7 gcm[tex]^{}-3[/tex] = 0.0007 gL[tex]^{}-1[/tex]
Therefore
density = mass/volume
0.0007 gL[tex]^{}-1[/tex] = mass / 1 L
0.0007g = mass
amount (of petrol) = mass/molar mass
= 0.0007/228
= 0.000003 mols
therefore...amount of oxygen is 25 times amount i got for petrol?
so
n(o) = 0.000003*25
then
0.000075 = mass/molar mass
0.000075 = mass/32
0.0024g = mass
Have i blown it somewhere? I am not sure about the mols thing i did when going from petrol to oxygen... I mean do you times it by 25 OR 12.5 because the mol ratio is 2petrol + 25Oxygen
i think times by 25 because when finding molar mass for petrol I multiplied everything by 2
btw the right answer is appparentlyyyy 2.5*10^3 grams, what did i do? ahh
cheers
2C8H18(g) + 25O2 -----> 16CO2 + 18H2O
The density of Ocatane is 0.7 gcm(cubed)
What mass of oxygen is used up when 1L of petrol is burnt in a car engine?
ATTEMPT
0.7 gcm[tex]^{}-3[/tex] = 0.0007 gL[tex]^{}-1[/tex]
Therefore
density = mass/volume
0.0007 gL[tex]^{}-1[/tex] = mass / 1 L
0.0007g = mass
amount (of petrol) = mass/molar mass
= 0.0007/228
= 0.000003 mols
therefore...amount of oxygen is 25 times amount i got for petrol?
so
n(o) = 0.000003*25
then
0.000075 = mass/molar mass
0.000075 = mass/32
0.0024g = mass
Have i blown it somewhere? I am not sure about the mols thing i did when going from petrol to oxygen... I mean do you times it by 25 OR 12.5 because the mol ratio is 2petrol + 25Oxygen
i think times by 25 because when finding molar mass for petrol I multiplied everything by 2
btw the right answer is appparentlyyyy 2.5*10^3 grams, what did i do? ahh
cheers