The Definition of Redshift for Photons

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In summary, the conversation is about the correct notation for associating energy with a timelike Killing vector field (KVF). The correct notation is ##\dot{t}^2##, not ##\dot{t}##. The confusion arises from confusing energy as measured by a particular observer and energy associated with a timelike KVF. The conversation also touches on the derivation of cosmological redshift in a flat FRW spacetime, where the ratio of the energies is proportional to the ratio of the proper times of the observers. The proper times
  • #36
PeterDonis said:
. The redshift of the photon, as you will see if you do this analysis, then turns out to be, as I said before, the ratio of the scale factor at reception to the scale factor at emission--more precisely, this ratio is equal to ##1 + z##, where ##z## is the redshift.

In previous posts I was trying to establish the definition of red shift, (well the predicted redshift not the lab spectral line observed measurement) and there was no such direct response, other than that of observation. Well if we determine ##k## by the method you described, and ##k## is such that the photon is null, then that is something we are comparing - you used the term red-shift twice above. Somehow it is plausible to immediately state that the 'red shift if the photon' is given by comparing these frequencies, but then you use redshift to refer to ##z## - the only mysterious definition I was pointed to. The important parameter was what I was after, so it's ##k## ? It's so obvious that you can compare frequencies to give the red shift if the photon that you don't even explain this, yet all my questions where pointed toward ##z## ...
 
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  • #37
binbagsss said:
In previous posts I was trying to establish the definition of red shift, (well the predicted redshift not the lab spectral line observed measurement) and there was no such direct response, other than that of observation.

Sure there was; I gave you the definition of redshift in post #32.

binbagsss said:
if we determine ##k## by the method you described, and ##k## is such that the photon is null

I don't know what you mean here; ##k## itself doesn't tell anything about whether the photon's worldline is timelike or null; you have to already know that the photon's worldline is null in order to determine ##k## by the method I described.

I've already said once that if you do the actual math, it will make all this a lot clearer. Have you done the actual math?

binbagsss said:
Somehow it is plausible to immediately state that the 'red shift if the photon' is given by comparing these frequencies, but then you use redshift to refer to z

I don't understand what your issue is. If you want the precise mathematical definition, here it is: we observe a particular spectral line in the lab to have a wavelength ##\lambda_{\text{lab}}##. We observe the same spectral line in light from a distant object to have a wavelength ##\lambda_{\text{obs}}##. Then

$$
1 + z = \frac{\lambda_{\text{obs}}}{\lambda_{\text{lab}}}
$$

If you want it in terms of frequencies instead, then we have the lab frequency ##\nu_{\text{lab}}## and the frequency observed from the distant object ##\nu_{\text{obs}}##, and then

$$
1 + z = \frac{\nu_{\text{lab}}}{\nu_{\text{obs}}}
$$

You can find these definitions in any textbook or in many places online; most of them will call ##\nu_{\text{lab}}## or ##\lambda_{\text{lab}}## the "emitted" frequency or wavelength, because we assume that the frequency/wavelength we observe in the lab will be the same as the frequency/wavelength emitted by the distant object (because the same substances should emit the same frequencies/wavelengths anywhere, since the physical laws governing emission are the same).

Is this what you were looking for? If not, what are you looking for?
 

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