- #1
Kieran Hall
- 10
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- TL;DR Summary
- The determination of a projectile's launch angle from a boom of angle theta
Hi, I am new here to the forum and I am having trouble with a project that I am undertaking with some friends.
We are trying to build a firefighting robot.
I am trying to derive an expression to solve for the launch angle theta of the water so that at x (meters), the projectile will be at 0.33 (meters) of height.
The water will be launched from a boom arm of length L (meters) as opposed to being projected at an angle from a height of 'h' (meters).
Obviously as the boom angle is changed, the height that the projectile is launched from will change as well.
I have tried to incorporate this height of the boom into my equation as 'L.Sin(theta)'.
This is the difficulty that I am having as I don't know if my equation can be solved and if not, I'm unsure how to calculate the required boom angle.
Any help will be extremely appreciated.
Thanks,
Kieran
We are trying to build a firefighting robot.
I am trying to derive an expression to solve for the launch angle theta of the water so that at x (meters), the projectile will be at 0.33 (meters) of height.
The water will be launched from a boom arm of length L (meters) as opposed to being projected at an angle from a height of 'h' (meters).
Obviously as the boom angle is changed, the height that the projectile is launched from will change as well.
I have tried to incorporate this height of the boom into my equation as 'L.Sin(theta)'.
This is the difficulty that I am having as I don't know if my equation can be solved and if not, I'm unsure how to calculate the required boom angle.
Any help will be extremely appreciated.
Thanks,
Kieran