MHB The distance from AB = BC. AB = x^2 and BC = 9. Find AC.

  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Ac
AI Thread Summary
The problem states that the distance from AB equals BC, with AB defined as x^2 and BC as 9. By solving for x, it is determined that x equals 3, making AB equal to 9. Since both AB and BC are 9, the total distance AC is calculated by adding AB and BC, resulting in AC being 18. The conclusion assumes AC is a straight line; alternative configurations may require different considerations. The final answer is that AC equals 18.
mathdad
Messages
1,280
Reaction score
0
Find Distance AC.

The distance from AB = BC. AB = x^2 and BC = 9. Find AC.

My Work:

A------x^2------B-----9----C

sqrt{x^2} = sqrt{9}

x = 3

Then x^2 = 3^2 = 9

If AB = 9 and BC = 9, then we add AB + BC to get the entire distance. This is basic geometry.

AC = 18

Correct?
 
Mathematics news on Phys.org
If AB = BC and BC = 9 then AB = 9. AB + BC = AC = 9 + 9 = 18.
 
greg1313 said:
If AB = BC and BC = 9 then AB = 9. AB + BC = AC = 9 + 9 = 18.

It feels good to be right.
 
That is assuming AC is a straight line, of course. If not, how do we answer?
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top