The Energy-Momentum Tensor

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The discussion clarifies the distinction between the stress-energy tensor in General Relativity and the energy-momentum tensor in Quantum Field Theory (QFT). The stress-energy tensor, defined as Tμν in the Einstein Field Equation, is not generally the same as the canonical energy-momentum tensor, Tμν in QFT. However, for scalar fields, both tensors yield equivalent results, differing only by a total divergence for other fields. The Belinfante–Rosenfeld stress-energy tensor can be modified from the canonical form to align with the Hilbert stress-energy tensor used in General Relativity. This understanding resolves the initial confusion regarding their equivalence.
agostino981
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I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$

Is it equivalent to the energy-momentum tensor I came across in QFT?

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$

Thanks in advance.
 
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agostino981 said:
I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$
This is the general definition of the SYMMETRICAL energy-momentum tensor.

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$
Thanks in advance.

This is the CANONICAL energy-momentum tensor. For scalar fields, the two are identical. For other fields they differ by a total divergence. They are equivalent in the sense that both leads to the same energy-momentum 4-vector
P^{ \mu } = \int d^{ 3 } x T^{ 0 \mu } ( x )
 
agostino981 said:
I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$

Is it equivalent to the energy-momentum tensor I came across in QFT?

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$

Thanks in advance.

They are not, in general, the same. However, in QFT, the stress-energy tensor is not unique, because you can add additional terms to it that have no effect on conservation laws. There is a procedure for tweaking the canonical stress-energy tensor to get a modified tensor, the Belinfante–Rosenfeld stress–energy tensor, that (according to Wikipedia, at least) agrees with the Hilbert stress-energy tensor used by General Relativity:
http://en.wikipedia.org/wiki/Belinfante–Rosenfeld_stress–energy_tensor
 
Wald has a good discussion of this, and shows that the first form arises naturalliy from formulating GR as a Lagrangian theory.
 
Thanks! That clears things up.
 
In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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