The equation of a line in 3space

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In summary, the task at hand is to find the parametric equations of a line that intersects both L1 and L2 at right angles. The method used is cross product to find the direction vector, which is [1,2,2]. However, finding the parametric equations proves to be difficult due to the skewed nature of the lines. Different attempts, such as setting the parametric equations equal to each other and using the s value to find the t value, have been made but do not match the given solution of (2,5,3). The suggestion is to find the distance squared between a point on each line and minimize it as a function of s and t to find the closest points and continue from there.
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Homework Statement



Find parametric equations of a line that intersect both L1 and L2 at right angles.
L1: [x,y,z]=[4,8,-1] + t[2,3,-4] L2: (x-7)/-6 = (y-2)/1 = (z+1)/2

Homework Equations



Symmetric, parametric, cross product

The Attempt at a Solution



We used cross product to find the direction vector, which was [1,2,2]. To finish the parametric equation, we need at least one of the points that this vector intersects the two lines (which are skewed).

One attempt was setting the two line's parametric equations equal to each other to isolate the t or s, and using this to find the x-, y- and z-value, this should not be possible though because the lines are skewed -- the t and s should not be equal to each other... But the numbers do satisfy each other (but not the back of the book -- the books example answer of a point (2,5,3) does not work).

We then tried taking the 's' we found, and put it into the parametric equations set to each other, to find the 't' at the set 's'. This resulted in -3/10, -1, -3/10. We then used these 't' values to find the x-, y- and z- values, and eventually make a parametric equation. This also does not work when we check it.
 
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Write both in parametric form. Let f = the distance squared between a point on one line and a point on the other. That will be a function of s and t. Minimize it as a function of s and t. Those values of s and t will give you the closest points and you can go from there.
 

FAQ: The equation of a line in 3space

1. What is the equation of a line in 3-space?

The equation of a line in 3-space is a mathematical expression that represents the relationship between the x, y, and z coordinates of a point on the line. It is typically written in the form of y = mx + b, where m is the slope of the line and b is the y-intercept.

2. How is the equation of a line in 3-space different from a line in 2D?

In 3-space, the equation of a line includes an additional variable, z, to represent the third dimension. This means that the equation will have three variables (x, y, and z) instead of just two (x and y) like in 2D. The equation also represents a line in three dimensions rather than just two dimensions.

3. How do you graph a line in 3-space using its equation?

To graph a line in 3-space using its equation, you will need to plot three points that satisfy the equation. These points should have different x, y, and z values. Once you have plotted the points, you can connect them to create the line in 3-space.

4. How do you find the slope and y-intercept of a line in 3-space?

To find the slope and y-intercept of a line in 3-space, you will need to rewrite the equation in the form of y = mx + b. From there, the slope (m) is the coefficient of the x term, and the y-intercept (b) is the constant term. If the equation is not in this form, you can rearrange it to find the slope and y-intercept.

5. Can the equation of a line in 3-space be written in other forms?

Yes, the equation of a line in 3-space can also be written in parametric form as (x,y,z) = (x0,y0,z0) + t(a,b,c), where (x0,y0,z0) is a point on the line and (a,b,c) is a direction vector. It can also be written in vector form as r = r0 + tv, where r is the position vector of a point on the line, r0 is a fixed point on the line, and v is a direction vector.

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