- #1
Amy06
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A courier is delivering a 5kg package to an office high in a tall building.
a) What upwards force does the courier apply to the package when carrying it horizontally at a constant velocity of 2m/s into the building?
B) The Courier uses the elevator to reach the office. While the elevator (Containing the courier holding the package) is accelerating at 0.11m/s/s, what upwards force does the courier apply to the package?
C) when the elevator is traveling upwards at a constant speed of 6m/s what upwards force deos the courier apply to the package?
D) in order to stop at the correct floor the elevator accelerates downwards at a rate of 0.2m/s. What is the upward force that the courier applies to the package during deacceleration?
Force= mass x acceleration
Weight = mass x gravity constant
A)
W= mg
= 5 x 9.81
= 49N upwards
(F=ma - f=5x2 f= 10N forwards)
B)
F= ma
= 5 x 0.11
= 0.55N upwards
However I am struggling with questions B,C and D as I don't know whether the 0.55N needs to be added to the 49N upwards already or whether it is just plain 0.55N. I think the courier applies the same 49N upwards and the elevator forces him up at 0.55N but I'm guessing this is wrong. Anyone know the answers or could help out with the remaining questions? Ta :)
a) What upwards force does the courier apply to the package when carrying it horizontally at a constant velocity of 2m/s into the building?
B) The Courier uses the elevator to reach the office. While the elevator (Containing the courier holding the package) is accelerating at 0.11m/s/s, what upwards force does the courier apply to the package?
C) when the elevator is traveling upwards at a constant speed of 6m/s what upwards force deos the courier apply to the package?
D) in order to stop at the correct floor the elevator accelerates downwards at a rate of 0.2m/s. What is the upward force that the courier applies to the package during deacceleration?
Force= mass x acceleration
Weight = mass x gravity constant
A)
W= mg
= 5 x 9.81
= 49N upwards
(F=ma - f=5x2 f= 10N forwards)
B)
F= ma
= 5 x 0.11
= 0.55N upwards
However I am struggling with questions B,C and D as I don't know whether the 0.55N needs to be added to the 49N upwards already or whether it is just plain 0.55N. I think the courier applies the same 49N upwards and the elevator forces him up at 0.55N but I'm guessing this is wrong. Anyone know the answers or could help out with the remaining questions? Ta :)