The Force Exerted by the Ground on a Parachuter

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The discussion revolves around calculating the force exerted by the ground on a parachutist who lands with an initial speed of 3.85 m/s and comes to rest over a distance of 0.700 m. The parachutist's mass is 35.5 kg, and the relevant equations include Fnet = m * anet and Vf^2 = Vo^2 + 2ax. Initial calculations yielded a deceleration of 10.5875 m/s², leading to a force of 375.86 N, but this was incorrect as it only accounted for the stopping force. The correct approach requires adding the weight of the parachutist to the stopping force to find the total force exerted by the ground. Understanding this distinction is crucial for accurately solving the problem.
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Homework Statement


A 35.5 kg parachutist lands moving straight downward with a speed of 3.85 m/s.
(a) If the parachutist comes to rest with constant acceleration over a distance of 0.700 m, what force does the ground exerts on her?

Variables: Vo, Vf, F, m, a, x
Known: Vo=3.85 (I think the problem means this as the initial)
m=35.5 kg
Vf=0 (don't quite understand the problem)
x=.7 m

Homework Equations


Fnet=m*anet
Possibly Vf^2=Vo^2+2ax

The Attempt at a Solution


I used Vf^2=Vo^2+2ax, and I got 10.5875 m/s^2, multiplied that by 35.5 kg, and I got 375.86 N. WebAssign says the answer is wrong.
 
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I figured it out. Apparently that is just the force required to stop the object--you must also factor in the weight.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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