The Klein bottle using the Euler caracteristic + orientability caracterisation

In summary, the conversation discusses the study of the Euler characteristic and orientability characterization of closed surfaces, specifically the Klein bottle. The speaker uses a formula for k and triangulates the Klein bottle to find its Euler characteristic, which should be 2 but is incorrectly calculated as 1. After further examination, it is determined that k should be 2, not 1.
  • #1
quasar987
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I went off on my own to study the Euler caracteristic + orentability caracterisation of closed surface and I must have gotten lost somewhere, because I do not find that the Klein bottle is homeomorphic to [itex]\mathbb{R}P^2\#\mathbb{R}P^2[/itex] as I should.

I started with the result that for two surfaces M and N, we have

[tex]\chi(M\#N)=\chi(M)+\chi(N)-2[/tex]

then I proved by induction that

[tex]\chi(M^{\#_k})=(k+1)\chi(M)-2k[/tex]

which can be solved for k:

[tex]k=\frac{\chi(M^{\#_k})-\chi(M)}{\chi(M)-2}[/tex]

Now, the Klein bottle is not orientable, so it must be homeomorphic to [itex](\mathbb{R}P^2)^{\#_k}[/itex] for some k. And since the Euler caracteristic is a topological invariant, it must be that

[tex]\chi((\mathbb{R}P^2)^{\#_k})=\chi(K)[/tex]

And so, according to the above formula for k, with [itex]\chi(M)=\chi(\mathbb{R}P^2)=1[/itex],

[tex]k=\frac{\chi(K)-1}{1-2}=1-\chi(K)[/tex]

So all that remains to do is to triangulate K and find its Euler caracteristic. A fundamental polygon for the Klein bottle is provided here:

http://en.wikipedia.org/wiki/Classification_theorems_of_surfaces#Construction_from_polygons

I believe it can be triangulated simply by drawing a side across one of the diagonal. All the vertices are identified, so V=1. There are 3 distinct sides, so E=3. My triangulation has 2 triangles so F=2, thus

[tex]\chi(K)=1-3+2=0[/tex]

But this means that k=1, which is incorrect. It should be 2.

Where did I go wrong?
 
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  • #2
well your euler characteristic calculation seems correct, since just looking at a picture of a klein bottle (the picture in my head) shows it obviously has the same edges faces and vertices as a torus, hence has the same euler chracteristic, namely zero. so the error is likely somewhere else.
 
  • #3
Whoah! There's no error at all !

[tex]\mathbb{R}P^2\#\mathbb{R}P^2 = (\mathbb{R}P^2)^{\#_1}[/tex]

k=1 is correct!

Edit: No! k should be 2 but I made an error in the very beginning by misinterpreting the #_k notation. I thought k referred to the number of # symbol, while it refers to the number of spaces you glue together.
 
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FAQ: The Klein bottle using the Euler caracteristic + orientability caracterisation

What is a Klein bottle?

A Klein bottle is a non-orientable surface that has only one side and cannot be embedded in three-dimensional space without self-intersection. It is a type of topological space that is often used in mathematics and physics for its unique properties.

How is the Euler characteristic used in the characterization of Klein bottles?

The Euler characteristic is a numerical value that is used to determine the topology of a surface. For a Klein bottle, the Euler characteristic is equal to 0, which indicates that it is a non-orientable surface with no boundary.

Can you explain the concept of orientability in relation to Klein bottles?

Orientability refers to the property of a surface to have a consistent orientation across the entire surface. In the case of Klein bottles, they are non-orientable because they cannot be consistently oriented due to their one-sided nature.

What are some real-life applications of Klein bottles?

Klein bottles are primarily used in mathematical and scientific research, particularly in topology and geometry. They are also used in physics, such as in the study of quantum mechanics and string theory.

Are there any visual representations of Klein bottles?

Yes, there are many visual representations of Klein bottles, including 3D printed models, computer-generated images, and physical sculptures. However, it is important to note that these representations are only approximations and cannot fully capture the unique properties of a true Klein bottle.

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