The last static equilibrium problem.

In summary, the conversation discusses a product liability lawsuit where an infant fell out of a portable seat supported by the edge of a table. The manufacturer claims that the child was too heavy for the seat, while the parents claim the seat was defective. Testing showed that the seat could withstand the weight of a child when certain forces were not exceeded. The child's mass was given as 10 kg. The conversation also includes calculations and a diagram, and concludes that the judge should rule in favor of the parents as the seat was proven to be defective.
  • #1
akan
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You have been called on to testify in a product liability lawsuit. An infant sitting in a portable seat that is supported by the edge of a table fell to the floor (see the figure). The manufacturer claims the child was too heavy for the seat, and the parents claim the seat was defective. Testing showed that the seat can withstand the weight of a child when the force at A does not exceed 96.2 N and the force at B does not exceed 229 N. The child has a mass of 10 kg. In whose favor should the judge rule?

http://img370.imageshack.us/img370/5152/rw1264ji6.jpg
http://g.imageshack.us/img370/rw1264ji6.jpg/1/

How do I solve this?
 
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  • #2
Hi akan! :smile:

Show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:
 
  • #3
(x) Sum(F_x) = 0 (no forces)
(y) Sum(F_y) = F_a - F_b - F_child = 0

F_child = mg = 10*9.8 = 98

pivot at B:
(2) Sum(T_z) = F_a * (.22) - F_child (.16) = 0

pivot at C (child):
(3) Sum(T_z) = F_a * (.38) - F_b (.16) = 0

(2) .22 F_a = .16 F_child
(2) F_a = (.16 / .22) F_child = (.16 / .22) (98) = 71.27

(3) (.16 / .22) F_child (.38) = F_b (.16)
(3) F_b = (.38 / .22) F_child = (.38 / .22) (98) = 169.272727

Neither of these exceeds the allowed values, so why is the correct answer "in favor of parents"?
 
  • #4
judge rules ok!

akan said:
Neither of these exceeds the allowed values, so why is the correct answer "in favor of parents"?
akan said:
You have been called on to testify in a product liability lawsuit. An infant sitting in a portable seat that is supported by the edge of a table fell to the floor (see the figure). The manufacturer claims the child was too heavy for the seat, and the parents claim the seat was defective. Testing showed that the seat can withstand the weight of a child when the force at A does not exceed 96.2 N and the force at B does not exceed 229 N. The child has a mass of 10 kg. In whose favor should the judge rule?

Hi akan! :smile:

I haven't checked your calculations …

but assuming they're correct, that means that the child would have been safe if the seat was well-made.

Since the child wasn't safe, that proves the seat was defective, and so the judge should rule "in favor of parents". :smile:
 
  • #5
The calculations show that the force did not exceed the specifications. Yeah, I guess that means that it's the manufacturer's fault and the seat was flawed. Thanks.
 

FAQ: The last static equilibrium problem.

What is "The last static equilibrium problem"?

The last static equilibrium problem refers to a physics problem that involves finding the final state of a system in which all forces are balanced. It is called the "last" static equilibrium problem because it involves finding the final state of a system after all forces have been applied.

What makes "The last static equilibrium problem" important?

The last static equilibrium problem is important because it allows scientists and engineers to understand how objects behave when all forces are balanced. This knowledge is essential for designing stable structures and predicting the movements of objects in various environments.

How is "The last static equilibrium problem" solved?

The last static equilibrium problem is solved by setting up and solving equations that represent all the forces acting on a system. This involves using principles of physics, such as Newton's laws of motion, to determine the final state of the system.

What are some real-world applications of "The last static equilibrium problem"?

The last static equilibrium problem has many real-world applications, such as designing buildings, bridges, and other structures to withstand external forces like wind and earthquakes. It is also used in fields like aerospace engineering to determine the stability of aircraft and spacecraft.

What are the limitations of "The last static equilibrium problem"?

The last static equilibrium problem assumes that all forces acting on a system are balanced, which is not always the case in real-world situations. It also does not take into account factors like friction, which can affect the final state of a system. Additionally, it may not be applicable to systems with complex or non-linear forces.

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