- #1
Organic
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A Marsian mathematician visiting Earth and wishes to understand how Earthman mathematician understand the limit concept.
After couple of hours of communication we have this situation:
1) a not= b
Earthman: By my way (1) is an hypothesis.
Marsian: By my way (1) is an invariant state.
2) abs(a-b)=d < e > 0
Earthman: a) By my way you compare d to set S that includes in it all R members > 0. in this case d<d is impossible; therefore d must be = 0 --> a=b
Earthman: b) Another version of my way is to say that e=d/2 but then |a-b|=d AND |a-b|<d/2 which is impossible; therefore a=b.
Marsian: e and d relation remaining unchanged in any arbitrary scale that you choose, which means: d is always smaller then e but greater than 0. It means that e=d/2 is impossible because e > d/n > 0.
Marsian: S is an open collection (has infinitely many elements) therefore cannot be completed by definition. Only finite collection can be a complete collection. Therefore there is no such thing like S which includes all r > 0.
Earthman: How a set cannot be completed? for example: please explain how N is not a complete collection of all n's by showing me n which is not in N.
Marsian: Natural numbers do not exist because of the existence of N, but because of the axioms that define them, N is only the name of the container that its content is infinitely many elements that can never be completed, and defined by the proper axiomatic system.
Earthman: e and d are fixed values.
Marsian: e and d are variables, and both of them are always greater than 0.
Options:
a) Earthman method is the right method.
b) Marsian method is the right method.
c) There is no one right method; therefore both methods are reasonable methods.
Please choose a, b or c or if you like, please add more options.
When you choosing or adding some option, please explain why do you choosing or adding it?
Thank you,
Organic
After couple of hours of communication we have this situation:
1) a not= b
Earthman: By my way (1) is an hypothesis.
Marsian: By my way (1) is an invariant state.
2) abs(a-b)=d < e > 0
Earthman: a) By my way you compare d to set S that includes in it all R members > 0. in this case d<d is impossible; therefore d must be = 0 --> a=b
Earthman: b) Another version of my way is to say that e=d/2 but then |a-b|=d AND |a-b|<d/2 which is impossible; therefore a=b.
Marsian: e and d relation remaining unchanged in any arbitrary scale that you choose, which means: d is always smaller then e but greater than 0. It means that e=d/2 is impossible because e > d/n > 0.
Marsian: S is an open collection (has infinitely many elements) therefore cannot be completed by definition. Only finite collection can be a complete collection. Therefore there is no such thing like S which includes all r > 0.
Earthman: How a set cannot be completed? for example: please explain how N is not a complete collection of all n's by showing me n which is not in N.
Marsian: Natural numbers do not exist because of the existence of N, but because of the axioms that define them, N is only the name of the container that its content is infinitely many elements that can never be completed, and defined by the proper axiomatic system.
Earthman: e and d are fixed values.
Marsian: e and d are variables, and both of them are always greater than 0.
Options:
a) Earthman method is the right method.
b) Marsian method is the right method.
c) There is no one right method; therefore both methods are reasonable methods.
Please choose a, b or c or if you like, please add more options.
When you choosing or adding some option, please explain why do you choosing or adding it?
Thank you,
Organic
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