The math involved in bending a rod

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To calculate the length of a door lever prior to bending, one must consider both the inner and outer radii of the bend. The outer radius can be approximated using the formula for the arc length of a quarter-circle, while also accounting for the straight sections of the lever. If the material, such as brass, stretches or compresses, this will affect the accuracy of the calculation. A practical approach is to bend a known length of rod, then measure and adjust based on the excess material removed. Ultimately, accurately modeling the lever in Solidworks may require precise material properties to ensure correct dimensions.
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I have a door lever which has a 90 deg. bend. I need to calculate the length that this lever would have to be if it were in the form of a straight rod, prior to being bent.

I know I have all the input data, I'm just not sure how to express this algebraically. For example, I know that the inner radius of the bend is 0.416", and the outer radius is 0.892". Based on this data, how can I calculate the length of the lever prior to being bent?

Thanks in advance!
 
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That would depend on how much the rod material can stretch and/or compress. Assuming no stretching, then the outer radius would consist of a quarter-circle having the same radius (0.892"). That arc would then have a length of 1/4 of the circumference of a 0.892" radius circle. Calculate that then add the straight lengths to it.

C=2\pi r

\frac{1}{4}C=\frac{\pi r}{2}

If the material stretches, this won't be accurate though.

It would be much easier to take a piece of rod of a known length, bend it, and cut off the amount you don't need. Subtract that amount (that was cut off) from your original length. That will give you the total length needed.
 
It is a nontrivial engineering problem and the answer will depend on properties of the material.

To the lowest approximation, it would probably be most accurate to assume that the outer half of the rod will stretch and the inner half will compress. So, the total length ~ straight lengths + pi r_c/2 where r_c = (0.416+0.892)/2.

My advice would be to do this experimentally, as the previous poster suggested.
 
Thanks for the help guys. The lever is actually made out of brass, so there is definitely some degree of stretching and compression. Here's the problem. Basically, what I am doing is a simple exercise in reverse engineering. I have a finished lever sample, and I am trying to duplicate it in Solidworks, but I need to model it in the form of a straight rod because it will be lathed then bent. I modeled the lever, applied a flex modifier and bent the digital rod to 90deg. However, when I supplied the drawings to the shop, the bend was completely off. Perhaps the problem is as simple as not having used the proper bending wheel during the bending process. Nonetheless, I want to re-evaluate my design, and mathematically calculate the dimensions to determine if my model was flawed to begin with. Do you think this can be done without having the exact physical properties of the material?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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