- #1
ksle82
- 30
- 0
Given 80 feet of fencing, what is the maximum area that you can enclose along a wall?
Solution:
L=lenght, W=width, A=area
2L+2W=80 (perimeter) ==> L+W=40 ==> L=40-W
LW=A ==> (40-W)(W)= -W^2+ 40W= A
(dA/dW)=0=-2W+40=0 ==> W=20
W=20, L=20--------------------------------------------------ANSWERS
Is this right? any input would be appreciated.
Solution:
L=lenght, W=width, A=area
2L+2W=80 (perimeter) ==> L+W=40 ==> L=40-W
LW=A ==> (40-W)(W)= -W^2+ 40W= A
(dA/dW)=0=-2W+40=0 ==> W=20
W=20, L=20--------------------------------------------------ANSWERS
Is this right? any input would be appreciated.