- #36
Doc Al
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Huh? Given the definition of work ([itex]\vec{F}\cdot \vec{s}[/itex]), and an understanding of Newton's laws, one derives the fact that [itex]W = \Delta (1/2mv^2)[/itex]. Yes, we call that quantity "Kinetic Energy", but regardless of the name it is still [itex]1/2mv^2[/itex].Eyesaw said:Yes, you showed that the second firing did 3 times more work, but did you show why 3 times more work didn't add 3 times more velocity to the pellet? No, the only answer you could give was that because K.E. is defined to be 1/2mv^2.
Not if you understand Newton's laws. A force can both do work on a particle leading to a change in KE and exert an impulse ([itex]\vec {F}\Delta t[/itex]) on a particle leading to a change in momentum.If K.E. was undefined and you started from rest and applied a constant force over 1 distance unit to achieve a velocity v for a particular mass, wouldn't it be reasonable to assume that if you applied the same force over 2 distances, you should achieve a final velocity of 2v?