The nature of light (can someone check my answer please)

[rojasharma]

1. Homework Statement
A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees


2. Homework Equations

Sin Theta(m) = (m + 0.5) Lambda/w

3. The Attempt at a Solution

Sin Theta(3) = (3 + 0.5)(633 x 10 e-9)/2.2 x 10 e-5
=(3.5)(633 x 10 e-9)/2.2 x 10 e-5
=0.1

Theta(3) = sin-1(0.1)
=5.7 degrees

Therefore, the position of the third maximum is at 5.7 degrees
Is this answer correct?

 

[anathema]

I would first like to commend you on using the correct formula and units in your solution. Your calculations and final answer appear to be correct. However, it is always important to check your work and make sure that you are using the correct values for the variables in the formula. In this case, the slit width is given in meters, but the wavelength is given in nanometers. It is important to convert the wavelength to meters before plugging it into the formula. Also, make sure that you are using the correct value for the slit width. Double check your calculations and units to ensure accuracy in your answer. Keep up the good work!

 

[Moetasim]

Yes, your answer is correct. The position of the third maximum in degrees is 5.7 degrees. This is determined using the equation for the position of the maximums in a single slit diffraction pattern, where m is the order of the maximum and lambda is the wavelength of the light. This calculation is important in understanding the behavior of light and its interactions with objects, and can be applied to various experiments and technologies such as diffraction gratings and interferometers.