The potential on the rim of a uniformly charged disk

In summary, the study of the electric potential on the rim of a uniformly charged disk involves analyzing the distribution of charge and its influence on the electric field at various points. By integrating the contributions from each infinitesimal charge element on the disk, the potential can be calculated, revealing how it varies with distance from the center and the overall configuration of the disk. The results indicate that the potential exhibits specific characteristics based on the disk's radius and charge density, providing insights into electrostatic behavior in similar geometries.
  • #1
chaos333
11
1
This comes from Griffiths' Electrodynamics and is problem 2.51 or 2.52, the disk has a surface charge density and my usual approach to solving these problems is to pick an area element and find a way to create a vector to the point(s) at which the potential is evaluated at. I sent a picture of my thought process and attempt at the problem. The solution involves a R^2+r^2-2Rrcos(theta) instead of R^2+r^2-2Rr that I have and I don't know how they arrived to that. Is my vector wrong or something else?
1720118052126.png
 
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  • #3
anuttarasammyak said:
The law of cosines https://en.m.wikipedia.org/wiki/Law_of_cosines might be helpful.
I understand the answer involves the law of cosine formula, but how was that derived from the vector?
 
  • #4
1720144524123.png


Here not Rr but ##\mathbf{R}\cdot\mathbf{r}##, an inner product, for [tex]|\mathbf{R}-\mathbf{r}|^2 =(\mathbf{R}-\mathbf{r})\cdot(\mathbf{R}-\mathbf{r})[/tex].
 
  • #5
anuttarasammyak said:
View attachment 347821

Here not Rr but ##\mathbf{R}\cdot\mathbf{r}##, an inner product, for [tex]|\mathbf{R}-\mathbf{r}|^2 =(\mathbf{R}-\mathbf{r})\cdot(\mathbf{R}-\mathbf{r})[/tex].
This makes a lot of sense now, thanks.
 
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FAQ: The potential on the rim of a uniformly charged disk

What is the electric potential at a point on the axis of a uniformly charged disk?

The electric potential at a point on the axis of a uniformly charged disk can be calculated using the formula: V(z) = (σ / (2ε₀)) * (R² - z²)^(1/2) + (σ / (2ε₀)) * ln((R + (R² + z²)^(1/2)) / z), where σ is the surface charge density, ε₀ is the permittivity of free space, R is the radius of the disk, and z is the distance from the center of the disk along the axis.

How does the radius of the disk affect the electric potential at the rim?

The radius of the disk affects the electric potential at the rim by influencing the distribution of charge and the resultant electric field. A larger radius typically results in a higher electric potential at the rim, as there is more charge contributing to the potential at that point. However, the relationship is not linear, as the potential also depends on the distance from the disk.

Is the electric potential uniform across the surface of the disk?

No, the electric potential is not uniform across the surface of the disk. The potential varies with the distance from the center of the disk, being highest at the center and decreasing towards the edge. This variation is due to the differing contributions of the charge elements to the potential at various points on the disk.

What is the significance of the potential at the rim of the disk in practical applications?

The potential at the rim of a uniformly charged disk is significant in various applications, such as in capacitors, sensors, and electronic devices. Understanding the potential distribution helps in designing components that rely on electric fields, such as in the optimization of electric field strength and energy storage capabilities.

How can the electric potential on the rim be experimentally measured?

The electric potential on the rim of a uniformly charged disk can be experimentally measured using a voltmeter or an electrostatic sensor. By placing the sensor at the rim and ensuring it is calibrated, one can measure the potential difference between the rim and a reference point, typically at infinity or ground, to determine the electric potential accurately.

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