The proof of Time Scaling, Laplace transform

In summary, the conversation discussed the determination of the time scale and how to go from the left-hand side to the right-hand side of equation 6.96. The speaker mentioned that the first attachment provides the full details, while the second attachment is the part they are stuck on. They explained that to go from the given equation, one must multiply -st in the exponential by a/a=1 and rewrite it as (s/a)(at). They also suggested using a new variable t' to simplify the integral.
  • #1
killahammad
5
0
Hi

I understand most of the steps in the determination of the time scale. But i don't really understand the step in equation 6.96.

The first attachment is the full details of the time scale, and the second attachment is the part which I am stuck on.

I just want to know, how they get from the LHS to the RHS of the equation

Thanks for any help :)
 

Attachments

  • scaling.png
    scaling.png
    12.3 KB · Views: 3,220
  • scaling2.png
    scaling2.png
    2 KB · Views: 1,403
Last edited:
Physics news on Phys.org
  • #2
to go from
[tex]\int_0^\infty e^{-st}f(at)dt[/tex]
You do 2 things: Multiply -st in the exponential by a/a= 1 and rewrite (st)(a/a)= (s/a)(at); also write (a/a)dt= (1/a)(adt). Since a is a constant, we can take the 1/a outside the integral and write adt= d(at). That gives you
[tex]\frac{1}{a}\int_0^\infty e^{-\frac{s}{a}}(at)f(at)d(at)[/tex]
Now, put in a new variable: let t'= at. Then dt'= d(at). When t= 0, u= t' and, as t goes to infinity, t' goes to infinity. In the variable t', f(at)= f(t') so we have
[tex]\frac{1}{a}\int_0^\infty e^{(s/a)t'} f(t)dt'[/tex]
 
  • #3
thank you very much, that helped me alot
 

FAQ: The proof of Time Scaling, Laplace transform

What is the Laplace transform and how does it relate to time scaling?

The Laplace transform is a mathematical tool used to convert a function from the time domain to the frequency domain. It is a powerful tool in solving differential equations and analyzing linear systems. Time scaling refers to the manipulation of the time variable in a function, and the Laplace transform allows us to easily analyze how a function changes with respect to time scaling.

What is the proof of time scaling using the Laplace transform?

The proof of time scaling using the Laplace transform is based on the property that the Laplace transform of a function f(at) is equal to 1/a times the Laplace transform of f(t). This means that when we scale the time variable by a, the Laplace transform of the function is also scaled by the same factor.

How is the proof of time scaling useful in real-world applications?

The proof of time scaling is useful in many real-world applications, especially in engineering and physics. It allows us to easily analyze the behavior of systems that involve time scaling, such as electrical circuits, mechanical systems, and chemical reactions. By using the Laplace transform, we can quickly and accurately predict how a system will respond to different time scales.

Can the proof of time scaling be extended to non-linear systems?

No, the proof of time scaling using the Laplace transform only applies to linear systems. Non-linear systems have more complex behaviors and cannot be analyzed using the Laplace transform. However, there are other mathematical tools that can be used to analyze non-linear systems.

Are there any limitations to the proof of time scaling?

Yes, the proof of time scaling using the Laplace transform is only valid for functions that have a Laplace transform. This means that the function must be continuous and have a finite number of discontinuities. Additionally, the function must approach zero as time goes to infinity. If these conditions are not met, the proof of time scaling may not be applicable.

Similar threads

Replies
1
Views
636
Replies
4
Views
2K
Replies
8
Views
2K
Replies
2
Views
1K
Replies
14
Views
2K
Replies
1
Views
1K
Back
Top