- #1
Jason Ko
- 19
- 6
The kinetic energy of a rotating rigid body is given by K=1/2mv^2 + 1/2Iw^2 but how to determine the proportion of translational energy and rotational energy? I know that if the mass distribution is more concentrated at its center mass, then more energy goes to the translational part. But is there actually a theorem account for it and how do we actually calculate the proportion?