The vector -5.2 has a magnitude of 32 and points in the positive direction.?

In summary, the conversation discusses finding the x component and magnitude of a vector, as well as determining its direction and magnitude based on given values. The speaker also expresses confusion about the given information and requests clarification. The expert provides a solution and explains the steps taken to find the desired values.
  • #1
MrGoodyear812
12
0
Find the x component of the vector A?

Find the magnitude of the vector A?

Please also explain your work too

thanks in advance
 
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  • #2
What do you mean by "the vector -5.2"?
 
  • #3
Hi MrGoodyear812, welcome to the PF.
You have not posted the actual problem. In the title, what is -5.2 and 32?
 
  • #4
OH! SORRY!

it should be the vectore

-5.2A
 
  • #5
MrGoodyear812 said:
OH! SORRY!

it should be the vectore

-5.2A
If you want the components of a vector, you most know the angle made by the vector with x-axis. What is that angle?
 
  • #6
rl.bhat said:
If you want the components of a vector, you most know the angle made by the vector with x-axis. What is that angle?

Thats why this problem is killing me...its not enough info

thats honestly everything the book gave us
 
  • #7
I don't get it, is -5.2A the name of the vector? That doesn't make any sense. Are -5 and 2 the components? Doesn't make sense that they would just ask for the x component. What the heck is the A for?

Maybe if you could write the problem statement word for word it would help.
 
  • #8
5.2 is the value of hte vector is what I am understanding...idk I am so confused...

and that is word for word
 
  • #9
Just got this email from my prof

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.
 
  • #10
He just emailed me this:

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.
 

FAQ: The vector -5.2 has a magnitude of 32 and points in the positive direction.?

What is the magnitude of the vector -5.2?

The magnitude of a vector refers to its length or size. In this case, the magnitude of the vector -5.2 is 32 units.

In which direction does the vector -5.2 point?

The vector -5.2 points in the positive direction. This means the vector extends in a direction that is to the right or above the origin, depending on the coordinate system used.

How is the direction of a vector determined?

The direction of a vector is determined by its angle with respect to a reference axis or direction. In this case, the vector -5.2 points in the positive direction, which means it forms an angle of 0 degrees with the positive x-axis.

Can a vector have a negative magnitude?

No, a vector cannot have a negative magnitude. Magnitude is a scalar quantity, meaning it only has a numerical value and does not have a direction. Therefore, it cannot be negative.

How is the magnitude of a vector calculated?

The magnitude of a vector is calculated using the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the lengths of the other two sides. In this case, the magnitude of the vector -5.2 can be calculated as √((-5.2)^2 + 0^2) = √27.04 = 32.

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