Virtual particles break conservation of energy in the classical sense. The maximum amount of extra energy can be [tex]\Delta E = \hbar / d[/tex], where [tex]d[/tex] is the distance between interacting particles. If you now count the wavelength of a photon of such energy, you will get exactly [tex]d[/tex].What does a wavelength even mean in this case?
The wavelength of virtual photons of the Coulomb force is not a well-defined quantity. Virtual photons are not actual particles and do not have a measurable wavelength like real photons do.
The wavelength of virtual photons does not directly affect the strength of the Coulomb force. The strength of the Coulomb force is determined by the charge and distance between two particles, not the wavelength of virtual photons.
No, the wavelength of virtual photons cannot be directly measured. They are a mathematical concept used to explain the behavior of the Coulomb force.
There is no direct relationship between the wavelength of virtual photons and the distance between charged particles. However, the exchange of virtual photons between two particles is what creates the Coulomb force, which does depend on the distance between the particles.
The wavelength of virtual photons is much shorter than the wavelength of real photons. Virtual photons are considered to have an infinitely small wavelength, while real photons have a measurable wavelength determined by their energy and frequency.