- #1
PainterGuy
- 940
- 70
hi everyone,
please see fig 42.25 a and b on this google doc:---
https://docs.google.com/viewer?a=v&...EyZGYtM2RmMTA3MDQxMTlm&hl=en&authkey=CKP-7OsD
i can understand the fig 42.25a and why the current flows. but i have questions about fig 42.25b.
what does the word 'biased' in "forward-biased" and "reverse-baised" mean as far as english meaning is concerned?
in fig 42.25b, positive terminal of battery will such electrons out of n-side which will leave behind 'positive' holes. negative terminal of battery will feed the electrons to holes in p-side. as n-side is deficient of electrons because positive terminal of battery has sucked them so this n-side will attract electrons out p-side which is now rich in electrons because negative terminal of battery has supplied electrons to p-side, so this will result in electric current. so there would also be current when battery terminals are reversed as in fig 14.25b. so where is i am wrong? please show me the light. thank you.
please see fig 42.25 a and b on this google doc:---
https://docs.google.com/viewer?a=v&...EyZGYtM2RmMTA3MDQxMTlm&hl=en&authkey=CKP-7OsD
i can understand the fig 42.25a and why the current flows. but i have questions about fig 42.25b.
what does the word 'biased' in "forward-biased" and "reverse-baised" mean as far as english meaning is concerned?
in fig 42.25b, positive terminal of battery will such electrons out of n-side which will leave behind 'positive' holes. negative terminal of battery will feed the electrons to holes in p-side. as n-side is deficient of electrons because positive terminal of battery has sucked them so this n-side will attract electrons out p-side which is now rich in electrons because negative terminal of battery has supplied electrons to p-side, so this will result in electric current. so there would also be current when battery terminals are reversed as in fig 14.25b. so where is i am wrong? please show me the light. thank you.