Thermal Physics, Homework #1 problem #1

In summary, for a large number of localized particles with spin 1/2 in an external magnetic field, the number of states accessible to the system can be calculated using the equation g(N,M)=N!/(Nup!Ndown!), and the entropy per particle can be calculated using the equation σ(N,U)=log(g(N,U)). To determine the value of M for which the number of states is a maximum, Stirling's Approximation can be applied to the equation σ(N,U)=ln[N!]-ln[Nup!]-ln[Ndown!], and the value of M will be 0 since the maximum of the Gaussian distribution will be when Nup=Ndown=N/2, resulting in M=0. This
  • #1
scikris
13
0
Consider a large number N of localized particles in an external magnetic field H. Each particle has spin 1/2.

Find the number of states, g(N,M), accessible to the system as a function of M=(Nup-Ndown), the magnetization.

Calculate the entropy per particle.

Determine the value of M for which the number of states is a maximum for a given N.


Equations that may help?
N=Nup+Ndown

M=Nup-Ndown

g(N,s)= N!/(Nup!Ndown!)

σ(N,U)=log(g(N,U))



This is my first thermal physics course and I am kinda confused (and overwhelmed) by this first homework assignment if anyone could explain what I am suposed to do, or set me in a direction, I would appreciate it.

Thanks in advance,
Kris
 
Physics news on Phys.org
  • #2
I should note, this homework is due tomorrow morning :(

any help appreciated!
 
  • #3
Are you familiar with Stirling's Approximation:

[tex]
\ln[N!]\approx N\ln[N]-N
[/tex]
 
  • #4
yes, the stirling's approximation just gives a means to calculate N! for very large N, but I still don't know how to apply that to entropy per particle...
 
  • #5
Use the equations you are given:

[tex]
\sigma=\ln\left[\frac{N!}{N_{up}!N_{down}!}\right]=\ln[N!]-\ln[N_{up}!]-\ln[N_{down}!]
[/tex]

Apply Stirling's approximation to the above, then use the fact that [itex]N=N_{up}+N_{down}[/itex] and [itex]M=N_{up}-N_{down}[/itex].
 
  • #6
okay thank you!,

"Determine the value of M for which the number of states is a maximum for a given N."
The value of M should be 0 correct?, because the middle of the Gaussian distribution will be centered at the origin. M=Nup-Ndown
 
  • #7
scikris said:
okay thank you!,

"Determine the value of M for which the number of states is a maximum for a given N."
The value of M should be 0 correct?, because the middle of the Gaussian distribution will be centered at the origin. M=Nup-Ndown

Correct, but I would say this as "the value of M will be zero because the maximum of the Gaussian distribution will be when [itex]N_{up}=N_{down}=N/2\rightarrow M=N_{up}-N_{down}=N_{up}-N_{up}=0[/itex]" rather than how you have it.
 
  • #8
okay cool, your equation didnt show up could you re-post it?
 
  • #9
That is weird, I thought \rightarrow worked here... It should read

[itex]N_{up}=N_{down}=N/2[/itex] --> [itex]M=N_{up}-N_{down}=N_{up}-N_{up}=0[/itex]
 
  • #10
thanks, I think I have got it now.
 

FAQ: Thermal Physics, Homework #1 problem #1

What is thermal physics?

Thermal physics is a branch of physics that deals with the study of heat, temperature, and their relationship to energy and work. It involves the study of the behavior of matter at the microscopic level and how it relates to macroscopic properties such as temperature and pressure.

What is the first law of thermodynamics?

The first law of thermodynamics states that energy cannot be created or destroyed, but it can be transferred or converted from one form to another. It is also known as the law of conservation of energy.

How is heat transfer different from temperature?

Heat transfer refers to the movement of thermal energy from one object to another, while temperature is a measure of the average kinetic energy of particles in an object. Heat transfer can cause a change in temperature, but they are not the same thing.

What is the difference between an insulator and a conductor?

An insulator is a material that does not allow heat to easily pass through it, while a conductor is a material that allows heat to flow through it easily. This is due to the differences in the way they interact with thermal energy and their atomic structures.

How does heat affect the properties of matter?

Heat can cause changes in the physical, chemical, and mechanical properties of matter. For example, heating a solid can cause it to melt into a liquid, and further heating can cause it to vaporize into a gas. Heat can also affect the rate of chemical reactions and the strength of materials.

Similar threads

Back
Top