Thermal Physics (Specific Heat Capacity)

In summary: The correct answer is B) 0<T<50°CIn summary, when body X with a temperature of 0°C is brought into thermal contact with body Y with a temperature of 100°C, the final equilibrium temperature T of the two bodies will be between 0°C and 50°C. This is determined by the fact that the specific heat capacity of X is greater than that of Y, leading to a heat exchange where the heat lost by Y is greater than the heat gained by X. Therefore, the correct answer is B) 0<T<50°C.
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Homework Statement


Body X whose temperature is 0 °C is brought into thermal contact with body Y of equal mass and temperature 100 °C. The only exchanges of heat that take place are between X and Y. The specific heat capacity of X is greater than that of Y. Which statement about the final equilibrium temperature T of the two bodies is correct?

A) T = 50 °C
B) 0 < T < 50 °C
C) 100 °C > T > 50 °C
D) Answer depends on value of mass

Homework Equations



E = MCΔt

The Attempt at a Solution


[/B]
Let the specific heat capacity (SHC) of X to be Cx and SHC of Y to be Cy.

Since the only heat exchange is between X and Y, the heat lost by body Y = heat gained by body X.

Therefore, we know Cx > Cy and MCxΔt = MCyΔt

Since the masses are equal we can cancel them off. We can also find an equation for Δt based of it's initial temperatures as stated above and it's final equilibrium temperature (T).

Therefore, Cx(T) = Cy(100-T)

We can rearrange to give Cx/Cy = (100-T)/(T). Since Cx>Cy, we can deduce that 100-T>T.

This gives the final equation 100 > 2T and finally 50 > T.

So the answer should be B) 0 < T < 50. However, the answer given in the book is A) T = 50°C. I can't tell where I've gone wrong during my working out? Logically, my answer B) seems to make sense too. If the SHC of X is more than Y, then it takes more energy to raise X by 1°C compared to Y. Therefore, the energy lost by Y when the temperature decreases by 1°C is less than the amount required by X to increase by 1°C. Therefore, for every 1°C of temperature body Y drops, body X will gain less than 1°C. Is the answer in the textbook wrong?
 
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You are correct; the book is wrong, if the problem is copied correctly.
 
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FAQ: Thermal Physics (Specific Heat Capacity)

1. What is thermal physics?

Thermal physics is a branch of physics that focuses on the study of heat and its transfer between different systems. It involves the use of mathematical models and principles to understand the behavior of matter at the microscopic level.

2. What is specific heat capacity?

Specific heat capacity is the amount of heat required to raise the temperature of a substance by one degree. It is a physical property of a material and is measured in units of energy per mass per degree (J/kg·K).

3. How is specific heat capacity calculated?

Specific heat capacity is calculated by dividing the amount of heat transferred to a substance by the change in temperature and the mass of the substance. It is represented by the formula Q = mcΔT, where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

4. Why is specific heat capacity important?

Specific heat capacity is important because it helps us understand how different materials respond to changes in temperature. It also plays a crucial role in various industrial and technological processes, such as designing heating and cooling systems, predicting the behavior of materials in extreme temperatures, and developing efficient energy storage devices.

5. How does specific heat capacity differ between substances?

The specific heat capacity of a substance depends on its molecular structure and the strength of its intermolecular forces. Substances with stronger intermolecular forces, such as water, have higher specific heat capacities compared to substances with weaker forces, such as metals. Additionally, the specific heat capacity can also vary with temperature and pressure.

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