Thermal Stress Problem- not sure how to attack this one

In summary, the equation F/A = -Y\alpha\Delta T gives the stress required to keep the length of a rod constant as its temperature changes. By substituting the equation for change in length, \Delta L = \alpha L_0\Delta T, into the thermal stress equation, F/A = Y(\Delta L/L_0 - \alpha\Delta T), we can show that the stress is equal to F/A = Y(\Delta L/L_0 - \alpha\Delta T) when the length is permitted to change by an amount \Delta L when its temperature changes by \Delta T.
  • #1
RoKr93
21
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Homework Statement


The equation [itex]F/A = -Y\alpha\Delta T[/itex] gives the stress required to keep the length of a rod constant as its temperature changes. Show that if the length is permitted to change by an amount [itex]\Delta L[/itex] when its temperature changes by [itex]\Delta T[/itex], the stress is equal to [itex]F/A = Y(\Delta L/L_0 - \alpha\Delta T)[/itex].


Homework Equations


thermal stress:
[itex]F/A = -Y\alpha\Delta T[/itex]

solution:
[itex]F/A = Y(\Delta L/L_0 - \alpha\Delta T)[/itex]

change in length:
[itex]\Delta L = \alpha L_0\Delta T[/itex]

The Attempt at a Solution


I figure this will have something to do with the area, as that's the only relation to the length I can see in the problem. I tried substituting A0 + deltaA in for A in the thermal stress equation, but that didn't seem to get me anywhere. Would really appreciate some direction with this one.
 
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  • #2
This is one of those questions where the answer seems so obvious that you are left wondering what method you are allowed to use. E.g., can you not argue that it's the same as allowing the rod to expand freely, then compressing it to length only ΔL longer than it started?
 

Related to Thermal Stress Problem- not sure how to attack this one

What is thermal stress and how does it affect materials?

Thermal stress is the strain or deformation that occurs in a material due to the difference in temperature between its inner and outer layers. When a material is exposed to high temperatures, it expands, and when it is cooled, it contracts. This expansion and contraction cause stress in the material, which can lead to cracking, warping, or other forms of damage.

What causes thermal stress in materials?

Thermal stress can be caused by a variety of factors, including sudden changes in temperature, uneven heating or cooling, and differences in the coefficient of thermal expansion between materials. Other factors such as external forces, such as pressure or vibration, can also contribute to thermal stress.

How can thermal stress be prevented?

Thermal stress can be prevented by using materials with similar coefficients of thermal expansion, designing structures with proper ventilation and insulation to regulate temperature, and avoiding sudden changes in temperature. It is also important to carefully consider the material and design of a structure to ensure it can withstand the expected range of temperatures.

What are the effects of thermal stress on different materials?

The effects of thermal stress can vary depending on the type of material. Metals, for example, are more susceptible to thermal stress than ceramics or polymers. Metals can experience changes in strength and ductility, while ceramics can crack or shatter. Polymers may deform or melt under extreme thermal stress.

How can thermal stress problems be addressed in a scientific manner?

Thermal stress problems can be addressed by conducting experiments and simulations to understand the behavior of materials under different thermal conditions, and by using mathematical models to predict the effects of thermal stress on structures. It is important to gather accurate data and analyze it carefully to develop effective solutions to thermal stress problems.

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