- #1
leafjerky
- 43
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Homework Statement
One m3 of an ideal gas expands in an isothermal process from 760 to 350 kPa. Determine the specific work done by the gas.
Homework Equations
ω=W/m
1W2=mRTln(P1/P2) = P1V1ln(P1/P2)
P1V1=P2V2
The Attempt at a Solution
P1V1ln(P1/P2) = (760)(1)ln(760/350) = 589.29kJ
V2=(760)(1)/(350) = 2.17m3
I tried doing PV=mRT using STP and my mass calculated was .31kg but it doesn't seem right. How do I find mass?