Thermo: Show that the internal energy at constant entropy and volume decrease

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The discussion focuses on demonstrating that internal energy decreases at constant entropy and volume during a spontaneous process. It utilizes the Clausius inequality, showing that for a closed system transitioning from one thermodynamic equilibrium state to another, the change in internal energy (ΔU) is negative. This is supported by the relationship ΔU = Q and the condition that the change in entropy (ΔS) must be greater than the heat transfer divided by temperature. The conclusion is that for a spontaneous process, the internal energy decreases, indicating that the system loses energy. The challenge of varying temperature during the process is acknowledged but not resolved.
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Homework Statement


Show that the internal energy at constant entropy and volume decrease for a spontaneous process

Homework Equations


F = U-TS

The Attempt at a Solution


Use Clausius: dS-dQ/dT > 0
Assume constant volume: TdS > dU
assume constant entropy
this becomes
0>dU

Since dU is negative, Change in F is negative thus spontaneous?
 
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You kind of had the right idea. For a constant volume process that transitions a closed system from thermodynamic equilibrium state A to thermodynamic equilibrium state B, you indicated that:
$$ΔU=Q$$
Also, from the Clausius inequality, for a spontaneous process,

$$ΔS>\frac{Q}{T_B}$$
where TB is the temperature at the heat transfer interface between the system and the surroundings, and where we have assumed that TB is held constant during the spontaneous process. Since ΔS is zero in the transition from state A to state B, we have:

$$0>\frac{Q}{T_B}$$

Therefore, Q<0, and ΔU<0.

I don't know how to do this if TB is varying during the process.
 

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