- #1
tom2tom
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1. A gas bottle with a volume of 0.1 m3 contains 0.4 kg of a gas at a pressure of 7
MN/m2 and a temperature of 150 ºC. For this gas Cp = 10.54 kJ/kg K. Calculate
the changes in internal energy when temperature is raised to 500K
Given answer: 362 kJ
2. pV=mRT pv=RT
mCpdT=dH
mCvdT=dU
dq-dw=du
3. so I've been struggling with this for a while. i know that du=dq as there is no net work when volume is constant.
initially i used p1V1/mT1=R and then i used Cp=R+Cv to find Cv. From there i used the equation mCvdT=dU. however this doesn't give the correct answer.
ive been trying a few other ways as well but they haven't worked. is there some assumption i can make etc...?
MN/m2 and a temperature of 150 ºC. For this gas Cp = 10.54 kJ/kg K. Calculate
the changes in internal energy when temperature is raised to 500K
Given answer: 362 kJ
2. pV=mRT pv=RT
mCpdT=dH
mCvdT=dU
dq-dw=du
3. so I've been struggling with this for a while. i know that du=dq as there is no net work when volume is constant.
initially i used p1V1/mT1=R and then i used Cp=R+Cv to find Cv. From there i used the equation mCvdT=dU. however this doesn't give the correct answer.
ive been trying a few other ways as well but they haven't worked. is there some assumption i can make etc...?