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Jess_18033152
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Homework Statement
A 77.1 kg hiker uses 191 kcal hr-1 (converted to 222.133 J.s ?) of energy whilst hiking. Assuming that 20% of this energy goes into useful work and the other 80% is converted to heat within the body, calculate the temperature change, in units of Kelvin (K), of the hiker's body during a 2.9 hour (converted to 10440s) long hike.
Assume that none of this generated heat is transferred to the environment during the hike. The average specific heat capacity of a human body is 0.83 kcal kg-1 oC-1. (converted to 3475.04 J/kg/K ?)
The answer needs to be given in Kelvin,
Homework Equations
Q = mc(change in temperature)
The Attempt at a Solution
Change in temp = Q/mc = 222.133/(77.1 x 3475.04)
=8.29 x 10^-4 K
Answer is wrong, I feel like I need to be using the time given also...