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Homework Statement
"A compressor takes air at 300K, 1 atm. It delivers compressed air at 2 atm, using 200W of power.
If the process is adiabatic and reversible, what is the rate that air is delivered, and what is the final temperature of the air? [k of air = 1.40]"
The Attempt at a Solution
Hi. I'd like to bounce off someone these expressions I derive, to see if they're sensible.
Since it's adiabatic, I infer that
[tex]PV^{K} = const[/tex]
Using the ideal gas law, and rearranging a bit, I make it that
[tex]T_{2} = \frac{P_{1}^{1/K-1}}{P_{2}^{1/K-1}}T_{1}[/tex]
I think that's sensible (?). It comes out as 366K.
For the last bit, I ended up deriving the expression
[tex]W = nR\frac{T_{1}-T_{2}}{1-1/K}[/tex]
which to me just looks too simple (it comes out as -1920J)
I started with the usual
[tex]W = \int^{V_{1}}_{V_{2}}p dV[/tex]
replacing dV with
[tex]-nRT\frac{dP}{P^{2}}[/tex]
and the T with
[tex]bP^{1-1/K}[/tex]
(b is a constant)
to obtain, in the end, the integral
[tex]W = -nRb \int^{P_{2}}_{P_{1}} P^{-1/K} dP[/tex]
On integrating, and then substituting for the b's in terms of T1 and P1 or T2 and P2, I found they disappeared, leaving me with
[tex]W = nR\frac{T_{1}-T_{2}}{1-1/K}[/tex]
But I'm not sure that's right (?). How does it look?
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