- #1
Sirsh
- 267
- 10
Homework Statement
[/B]Homework Equations
Assumptions[/B]: Closed System and Quasi-static.
p = 90 + 73,386*V -> V = (p-90)/(73,386)
v = V/m
Q - W = U2 - U1
mass balance: m = m1 = m2
The Attempt at a Solution
At state 1:
p1 = 110 kPa
V1 = (110-90)/(73,386) = 2.725*10-4 m3
v1 = V1/m1 = 2.725*10-4 / 0.1 = 2.725*10-3 m3/kg
At state 2:
p2 = 1000 kPa
V2 = (1000-90)/(73,386) = 124.002*10-4 m3
v2 = V2/m2 = 124.002*10-4 / 0.1 = 124.002*10-3 m3/kg
Now I've got two independent properties of the steam at states 1 and 2, pressure and specific volume. I should be able to use these to find their respective internal energies from the steam tables. However, I cannot find where to get these points.. As I'm thinking that by getting the internal energies I can substitute them into the No Flow Energy Equation and find the heat added as there is no work into or out of the system thus:
Qin = U2-U1
Any help in the right direction would be appreciated greatly.